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Top 100 Mathematics Formulae for School Students – A Complete Guide by Dhingra Classes Nashik

Mathematics is often considered the backbone of academic success. Whether you are studying in CBSE, ICSE, or SSC board, mastering mathematical formulae is essential for solving problems quickly and accurately. From basic arithmetic to advanced algebra and geometry, formulas are the building blocks of mathematics. At Dhingra Classes Nashik, we believe that a strong grasp of formulas is key to scoring high marks in board examinations. Our students, including Tejasi Ware (99.2%), Himanshi Dhingra (98.6%), Aavni Shinde (92.00%), and Akshitaa Sonar (91.6%), have consistently excelled in Mathematics by mastering these essential formulas.

In this comprehensive guide, we present the top 100 mathematics formulae for school students from Class 6 to 10. These formulas are categorized by topic for easy reference and revision.


📐 Number Systems & Arithmetic

FormulaDescription
(a + b)² = a² + 2ab + b²Square of a binomial (sum)
(a – b)² = a² – 2ab + b²Square of a binomial (difference)
a² – b² = (a + b)(a – b)Difference of squares
(a + b)³ = a³ + 3a²b + 3ab² + b³Cube of a binomial (sum)
(a – b)³ = a³ – 3a²b + 3ab² – b³Cube of a binomial (difference)
a³ + b³ = (a + b)(a² – ab + b²)Sum of cubes
a³ – b³ = (a – b)(a² + ab + b²)Difference of cubes
(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2caSquare of a trinomial
LCM × HCF = Product of two numbersRelationship between LCM and HCF
Percentage = (Part / Whole) × 100Percentage formula
Profit = SP – CPProfit calculation
Loss = CP – SPLoss calculation
Profit % = (Profit / CP) × 100Profit percentage
Loss % = (Loss / CP) × 100Loss percentage
SP = CP × (100 + Profit%) / 100Selling price with profit
SP = CP × (100 – Loss%) / 100Selling price with loss
Simple Interest = (P × R × T) / 100Simple interest formula
Compound Interest = P(1 + R/100)^T – PCompound interest formula
Amount = P(1 + R/100)^TAmount with compound interest

📐 Algebra

FormulaDescription
Linear Equation: ax + b = 0Standard form of linear equation
Quadratic Equation: ax² + bx + c = 0Standard form of quadratic equation
Quadratic Formula: x = [-b ± √(b² – 4ac)] / 2aSolution of quadratic equation
Discriminant: D = b² – 4acDetermines nature of roots
Roots: α + β = -b/a, αβ = c/aSum and product of roots
Arithmetic Progression: a_n = a + (n – 1)dnth term of AP
Sum of AP: S_n = n/2 [2a + (n – 1)d]Sum of n terms of AP
Geometric Progression: a_n = ar^{n-1}nth term of GP
Sum of GP: S_n = a(1 – r^n) / (1 – r)Sum of n terms of GP
Factorial: n! = n × (n – 1) × … × 1Factorial notation
Permutation: nPr = n! / (n – r)!Permutations
Combination: nCr = n! / [r!(n – r)!]Combinations
Binomial Theorem: (x + y)^n = Σ nCr x^{n-r} y^rBinomial expansion

📐 Geometry

FormulaDescription
Area of Rectangle = l × bArea formula
Perimeter of Rectangle = 2(l + b)Perimeter formula
Area of Square = side²Area formula
Perimeter of Square = 4 × sidePerimeter formula
Area of Triangle = ½ × b × hArea formula
Heron’s Formula: Area = √[s(s-a)(s-b)(s-c)]Area of triangle using semi-perimeter
Semi-perimeter: s = (a + b + c) / 2Semi-perimeter of triangle
Area of Parallelogram = b × hArea formula
Area of Rhombus = ½ × d₁ × d₂Area using diagonals
Area of Trapezium = ½ × (a + b) × hArea formula
Area of Circle = πr²Area of circle
Circumference of Circle = 2πrCircumference formula
Area of Sector = (θ/360) × πr²Area of sector
Length of Arc = (θ/360) × 2πrArc length
Area of Semicircle = ½ × πr²Area of semicircle
Perimeter of Semicircle = πr + 2rPerimeter of semicircle
Pythagoras Theorem: a² + b² = c²Right triangle relation
Euclid’s Division Lemma: a = bq + rDivision algorithm
Angle Sum Property: Sum of angles in triangle = 180°Triangle angle sum
Sum of Exterior Angles = 360°Polygon exterior angle sum
Interior Angle of Regular Polygon = (n – 2) × 180° / nInterior angle formula
Diagonals of Polygon = n(n – 3) / 2Number of diagonals

📐 Mensuration (3D Shapes)

FormulaDescription
Volume of Cube = side³Volume formula
Surface Area of Cube = 6side²Total surface area
Volume of Cuboid = l × b × hVolume formula
Surface Area of Cuboid = 2(lb + bh + hl)Total surface area
Volume of Cylinder = πr²hVolume formula
Curved Surface Area of Cylinder = 2πrhLateral surface area
Total Surface Area of Cylinder = 2πr(r + h)Total surface area
Volume of Cone = ⅓πr²hVolume formula
Slant Height of Cone: l = √(r² + h²)Slant height
Curved Surface Area of Cone = πrlLateral surface area
Total Surface Area of Cone = πr(r + l)Total surface area
Volume of Sphere = ⁴/₃πr³Volume formula
Surface Area of Sphere = 4πr²Surface area
Volume of Hemisphere = ⅔πr³Volume formula
Curved Surface Area of Hemisphere = 2πr²Curved surface area
Total Surface Area of Hemisphere = 3πr²Total surface area
Volume of Frustum = (πh/3)(R² + r² + Rr)Frustum volume
Curved Surface Area of Frustum = πl(R + r)Lateral surface area

📐 Trigonometry

FormulaDescription
sin θ = Opposite / HypotenuseSine ratio
cos θ = Adjacent / HypotenuseCosine ratio
tan θ = Opposite / AdjacentTangent ratio
cot θ = Adjacent / OppositeCotangent ratio
sec θ = Hypotenuse / AdjacentSecant ratio
cosec θ = Hypotenuse / OppositeCosecant ratio
sin²θ + cos²θ = 1Pythagorean identity
1 + tan²θ = sec²θPythagorean identity
1 + cot²θ = cosec²θPythagorean identity
sin(90° – θ) = cos θComplementary angles
cos(90° – θ) = sin θComplementary angles
tan(90° – θ) = cot θComplementary angles
sin 0° = 0, sin 30° = ½, sin 45° = 1/√2, sin 60° = √3/2, sin 90° = 1Standard values
cos 0° = 1, cos 30° = √3/2, cos 45° = 1/√2, cos 60° = ½, cos 90° = 0Standard values
tan 0° = 0, tan 30° = 1/√3, tan 45° = 1, tan 60° = √3Standard values

📐 Statistics & Probability

FormulaDescription
Mean (Direct Method) = Σxi / nArithmetic mean
Mean (Assumed Mean) = a + Σfidi / ΣfiMean using assumed mean
Mean (Step Deviation) = a + h × Σfiui / ΣfiMean using step deviation
Median (Odd n) = (n+1)/2th observationMedian for odd number of observations
Median (Even n) = Average of n/2th and (n/2+1)th observationsMedian for even number
Mode = Value with highest frequencyMode definition
Range = Maximum – MinimumRange formula
Variance = Σ(xi – μ)² / nPopulation variance
Standard Deviation = √VarianceStandard deviation
Probability = Favorable Outcomes / Total OutcomesProbability formula
P(A ∪ B) = P(A) + P(B) – P(A ∩ B)Union of two events
P(A ∩ B) = P(A) × P(B)Intersection of independent events
P(A / B) = P(A ∩ B) / P(B)Conditional probability

📐 Coordinate Geometry

FormulaDescription
Distance Formula: d = √[(x₂ – x₁)² + (y₂ – y₁)²]Distance between two points
Midpoint Formula: M = [(x₁ + x₂)/2, (y₁ + y₂)/2]Midpoint of a line segment
Section Formula: (mx₂ + nx₁)/(m+n), (my₂ + ny₁)/(m+n)Point dividing a line segment
Slope: m = (y₂ – y₁) / (x₂ – x₁)Slope of a line
Equation of Line: y = mx + cSlope-intercept form
Equation of Line: y – y₁ = m(x – x₁)Point-slope form
Equation of Line: (y – y₁)/(y₂ – y₁) = (x – x₁)/(x₂ – x₁)Two-point form
**Distance from Point to Line =Ax₁ + By₁ + C/ √(A² + B²)**Perpendicular distance

📐 Quadratic Equations & Polynomials

FormulaDescription
Quadratic Equation: ax² + bx + c = 0Standard form
Discriminant: D = b² – 4acDetermines nature of roots
Roots: x = (-b ± √D) / 2aQuadratic formula
Sum of Roots: α + β = -b/aSum of roots
Product of Roots: αβ = c/aProduct of roots
Nature of Roots (D > 0): Real & unequalDiscriminant > 0
Nature of Roots (D = 0): Real & equalDiscriminant = 0
Nature of Roots (D < 0): No real rootsDiscriminant < 0

How Dhingra Classes Helps Students Master Mathematics

At Dhingra Classes Nashik, we help students:

  • Master mathematical formulas through regular practice.

  • Apply formulas to solve complex problems.

  • Develop speed and accuracy through mock tests.

  • Build conceptual clarity in all topics.


Contact Dhingra Classes

  • Phone: 98230 62106

  • Email: dhingraclassesnsk@gmail.com

  • Website: www.dhingraclassesnashik.com

  • Address:Plot No 3, XQ3G+H3M Deacon Homes, 301C, opp. Metro Zone, near Guru Govind Sing, Samarth Nagar, Dnyaneshwar Nagar, Pathardi Phata, Nashik, Maharashtra 422009


Conclusion

Mastering the top 100 mathematics formulae for school students is essential for solving problems quickly and scoring high marks in board examinations. By memorizing and practicing these formulas, students can approach mathematics with confidence and ease. At Dhingra Classes Nashik, we are committed to helping students build a strong mathematical foundation and achieve academic excellence.