Are you a Class 9 CBSE student who has already solved our first Mathematics paper? At Dhingra Classes, we believe that the more you practise with fresh questions, the stronger your problem-solving skills become. This is Question Paper Set 2 — featuring completely new questions with answers and zero duplicates from our previous paper.
This paper covers nine crucial chapters from your new NCERT Ganita Manjari textbook: Orienting Yourself: The Use of Coordinates, Introduction to Linear Polynomials, Exploring Algebraic Identities, I’m Up and Down, Round and Round, Measuring Space: Perimeter and Area, The Mathematics of Mayhem: Introduction to Probability, Predicting What Comes Next: Exploring Sequences and Progressions, Sets, and Coordinate Geometry.
📋 CBSE Class 9 Mathematics Exam Pattern — 80 Marks (Set 2)
| Section | Question Type | Marks |
|---|---|---|
| Section A | Multiple Choice Questions (MCQ) | 20 × 1 = 20 |
| Section B | Very Short Answer Questions | 5 × 2 = 10 |
| Section C | Short Answer Questions | 6 × 3 = 18 |
| Section D | Long Answer Questions | 4 × 5 = 20 |
| Section E | Case Study Questions | 3 × 4 = 12 |
Time Allowed: 3 Hours
Maximum Marks: 80
📝 SECTION A: Multiple Choice Questions (20 × 1 = 20 Marks)
Q1. The ordinate of a point is its distance from the:
(a) x-axis
(b) y-axis
(c) origin
(d) z-axis
Answer: (a) x-axis
Q2. The point (-5, -7) lies in which quadrant?
(a) I
(b) II
(c) III
(d) IV
Answer: (c) III
Q3. The coordinates of a point on the y-axis are of the form:
(a) (x, 0)
(b) (0, y)
(c) (x, y)
(d) (0, 0)
Answer: (b) (0, y)
Q4. A linear polynomial has degree:
(a) 0
(b) 1
(c) 2
(d) 3
Answer: (b) 1
Q5. If p(x) = 4x – 9, then p(2) equals:
(a) -1
(b) 1
(c) 8
(d) 17
Answer: (a) -1
Q6. The zero of the polynomial p(x) = 2x + 8 is:
(a) 4
(b) -4
(c) 2
(d) -2
Answer: (b) -4
Q7. The identity a² – b² equals:
(a) (a + b)(a + b)
(b) (a – b)(a – b)
(c) (a + b)(a – b)
(d) (a + b)² – 2ab
Answer: (c) (a + b)(a – b)
Q8. Using the identity (a + b)² = a² + 2ab + b², the value of 101² is:
(a) 10201
(b) 10211
(c) 10101
(d) 10301
Answer: (a) 10201
Q9. The centre of a circle is the point of intersection of:
(a) Its chords
(b) Its diameters
(c) Its tangents
(d) Its arcs
Answer: (b) Its diameters
Q10. The longest chord of a circle is called:
(a) Radius
(b) Diameter
(c) Tangent
(d) Secant
Answer: (b) Diameter
Q11. The circumference of a circle with diameter 14 cm is (Take π = 22/7):
(a) 22 cm
(b) 44 cm
(c) 88 cm
(d) 154 cm
Answer: (b) 44 cm
Q12. The area of a triangle with base 12 cm and height 8 cm is:
(a) 96 cm²
(b) 48 cm²
(c) 24 cm²
(d) 20 cm²
Answer: (b) 48 cm²
Q13. The lateral surface area of a cylinder with radius 7 cm and height 10 cm is (Take π = 22/7):
(a) 220 cm²
(b) 440 cm²
(c) 660 cm²
(d) 880 cm²
Answer: (b) 440 cm²
Q14. When a fair die is rolled, the probability of getting a prime number is:
(a) 1/6
(b) 1/3
(c) 1/2
(d) 2/3
Answer: (c) 1/2
Q15. If the probability of an event is 1, then the event is:
(a) Impossible
(b) Certain
(c) Unlikely
(d) Likely
Answer: (b) Certain
Q16. The common difference of the AP: 7, 4, 1, -2, … is:
(a) 3
(b) -3
(c) 4
(d) -4
Answer: (b) -3
Q17. The 7th term of the AP: 2, 7, 12, 17, … is:
(a) 27
(b) 32
(c) 37
(d) 42
Answer: (b) 32
Q18. Which of the following is a null set?
(a) {0}
(b) {x : x is a natural number less than 1}
(c) {x : x is an even prime number}
(d) {1}
Answer: (b) {x : x is a natural number less than 1}
Q19. If A = {2, 4, 6} and B = {1, 2, 3, 4}, then A – B is:
(a) {6}
(b) {1, 3}
(c) {2, 4}
(d) {1, 2, 3, 4, 6}
Answer: (a) {6}
Q20. The number of subsets of a set with 3 elements is:
(a) 3
(b) 6
(c) 8
(d) 9
Answer: (c) 8
📝 SECTION B: Very Short Answer Questions (5 × 2 = 10 Marks)
Q21. Find the distance of the point P(-6, 8) from the origin. (2 marks)
Answer:
Distance = √(x² + y²)
= √((-6)² + (8)²)
= √(36 + 64)
= √100
= 10 units
Q22. Find the zero of the polynomial p(x) = 5x – 15. (2 marks)
Answer:
Set p(x) = 0:
5x – 15 = 0
5x = 15
x = 3
The zero of the polynomial is x = 3.
Q23. Using the identity (a – b)² = a² – 2ab + b², evaluate 99². (2 marks)
Answer:
99² = (100 – 1)²
= (100)² – 2(100)(1) + (1)²
= 10000 – 200 + 1
= 9801
Q24. A bag contains 4 white balls, 5 black balls, and 6 red balls. One ball is drawn at random. Find the probability of getting a white ball. (2 marks)
Answer:
Total balls = 4 + 5 + 6 = 15
Number of white balls = 4
P(white ball) = 4/15
Q25. Find the 15th term of the AP: 10, 13, 16, 19, … (2 marks)
Answer:
Given: a = 10, d = 3, n = 15
aₙ = a + (n – 1)d
a₁₅ = 10 + (15 – 1)(3)
= 10 + 42
= 52
📝 SECTION C: Short Answer Questions (6 × 3 = 18 Marks)
Q26. Plot the points P(1, 2), Q(1, -3), R(-4, -3), and S(-4, 2) on a Cartesian plane. Name the figure formed and find its area. (3 marks)
Answer:
The figure formed is a rectangle.
Dimensions:
Length (PQ) = 5 units (from 2 to -3)
Breadth (QR) = 5 units (from 1 to -4)
Area = Length × Breadth = 5 × 5 = 25 square units
Q27. If p(x) = 2x² – 5x + 3, find p(1) and p(-1) . (3 marks)
Answer:
p(1) = 2(1)² – 5(1) + 3
= 2 – 5 + 3
= 0
p(-1) = 2(-1)² – 5(-1) + 3
= 2 + 5 + 3
= 10
Q28. Using a suitable identity, evaluate 98 × 102. (3 marks)
Answer:
98 × 102 = (100 – 2)(100 + 2)
Using identity (a – b)(a + b) = a² – b²:
= (100)² – (2)²
= 10000 – 4
= 9996
Q29. In a circle of radius 13 cm, a chord is at a distance of 5 cm from the centre. Find the length of the chord. (3 marks)
Answer:
Using the formula: Chord length = 2√(r² – d²)
= 2√(13² – 5²)
= 2√(169 – 25)
= 2√144
= 2 × 12
= 24 cm
Q30. Find the area and perimeter of a rectangle with length 12 cm and breadth 5 cm. Also find the length of its diagonal. (3 marks)
Answer:
Area = l × b = 12 × 5 = 60 cm²
Perimeter = 2(l + b) = 2(12 + 5) = 2 × 17 = 34 cm
Diagonal = √(l² + b²) = √(12² + 5²) = √(144 + 25) = √169 = 13 cm
Q31. In a box, there are 8 red marbles, 7 blue marbles, and 5 green marbles. One marble is drawn at random. Find the probability of getting:
(a) a red marble
(b) a blue or green marble (3 marks)
Answer:
Total marbles = 8 + 7 + 5 = 20
(a) P(red marble) = 8/20 = 2/5 = 0.4
(b) P(blue or green marble) = (7 + 5)/20 = 12/20 = 3/5 = 0.6
📝 SECTION D: Long Answer Questions (4 × 5 = 20 Marks)
Q32. (a) State the identity for (a – b)³.
(b) Using this identity, expand (x – 2y)³. (5 marks)
Answer:
(a) (a – b)³ = a³ – b³ – 3ab(a – b)
= a³ – 3a²b + 3ab² – b³
(b) (x – 2y)³
= (x)³ – 3(x)²(2y) + 3(x)(2y)² – (2y)³
= x³ – 6x²y + 12xy² – 8y³
Q33. (a) Define a geometric progression.
(b) Find the 8th term of the GP: 2, 6, 18, 54, … (5 marks)
Answer:
(a) A geometric progression is a sequence in which each term after the first is obtained by multiplying the preceding term by a fixed non-zero number called the common ratio (r).
(b) Given: a = 2, r = 3, n = 8
aₙ = a × r⁽ⁿ⁻¹⁾
a₈ = 2 × 3⁷
= 2 × 2187
= 4374
Q34. (a) What is the difference between a finite set and an infinite set?
(b) If U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, A = {2, 4, 6, 8, 10}, and B = {1, 3, 5, 7, 9}, find A’ and B’. (5 marks)
Answer:
(a)
A finite set has a countable number of elements. Example: {1, 2, 3}
An infinite set has an uncountable or endless number of elements. Example: The set of all natural numbers
(b)
A’ = U – A = {1, 3, 5, 7, 9}
B’ = U – B = {2, 4, 6, 8, 10}
Q35. A point Q(5, -4) is given. (5 marks)
(a) In which quadrant does Q lie?
(b) Find its distance from the x-axis and y-axis.
(c) If Q is reflected across the x-axis, find the coordinates of the new point.
Answer:
(a) Q(5, -4) lies in Quadrant IV (x is positive, y is negative).
(b) Distance from x-axis = |-4| = 4 units
Distance from y-axis = |5| = 5 units
(c) Reflecting across the x-axis changes the sign of the y-coordinate:
New point = (5, 4)
📝 SECTION E: Case Study Questions (3 × 4 = 12 Marks)
Q36. Read the passage and answer the questions below:
A cricket match is being played. The probability that Team A wins is 0.6, and the probability that Team B wins is 0.3.
(a) What is the probability that the match ends in a draw? (2 marks)
Answer:
P(draw) = 1 – (P(A wins) + P(B wins))
= 1 – (0.6 + 0.3)
= 1 – 0.9
= 0.1
(b) What is the probability that Team A does not win? (2 marks)
Answer:
P(A does not win) = 1 – P(A wins)
= 1 – 0.6
= 0.4
Q37. Read the passage and answer the questions below:
A circular park has a radius of 21 m. The municipality wants to build a walking track around it. (Take π = 22/7)
(a) Find the circumference of the park. (1 mark)
Answer:
Circumference = 2πr
= 2 × (22/7) × 21
= 132 m
(b) Find the area of the park. (1 mark)
Answer:
Area = πr²
= (22/7) × (21)²
= (22/7) × 441
= 1386 m²
(c) If the walking track is 3.5 m wide, find the area of the track. (2 marks)
Answer:
Outer radius = 21 + 3.5 = 24.5 m
Area of track = π(R² – r²)
= (22/7) × (24.5² – 21²)
= (22/7) × (600.25 – 441)
= (22/7) × 159.25
= 500.5 m²
Q38. Read the passage and answer the questions below:
A savings scheme offers increasing deposits each month. The deposit amounts follow the pattern: ₹500, ₹550, ₹600, ₹650, … This follows an arithmetic progression.
(a) Find the common difference of this AP. (1 mark)
Answer:
d = 550 – 500 = ₹50
(b) Find the nth term formula for this AP. (1 mark)
Answer:
aₙ = a + (n – 1)d
aₙ = 500 + (n – 1)(50)
= 500 + 50n – 50
= 50n + 450
(c) What will be the deposit in the 12th month? (2 marks)
Answer:
a₁₂ = 50(12) + 450
= 600 + 450
= ₹1050
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🎯 Exam Tips for CBSE Class 9 Mathematics Students
Practise MCQs daily — they carry 20 marks in Section A
Memorise all algebraic identities — they are frequently tested
Draw neat diagrams for coordinate geometry and circle problems
Show step-by-step calculations in long answer questions
Link concepts to real-life examples — case study questions test application
